go Log1p()

Log1p()方法语法

func Log1p(x float64) float64

go源码对Log1p()方法的介绍:

Log1p returns the natural logarithm of 1 plus its argument x. It is more accurate than Log(1 + x) when x is near zero.

Special cases are:

Log1p(+Inf) = +Inf
Log1p(±0) = ±0
Log1p(-1) = -Inf
Log1p(x < -1) = NaN

golang模块math.Log1p()方法,所求的自然对数值类似于Log(1+x),但是在求参数x接近0的情况之时,Log1p()方法更加精确。除此之外,Log1p(+Inf) = +Inf;Log1p(±0) = ±0;Log1p(-1) = -Inf;Log1p(x < -1) = NaN;Log1p(NaN) = NaN。


math.Log1p()方法实例代码

func main() {
	log1p_v := math.Log1p(0.1)
	fmt.Println(log1p_v)
}

运行go文件,得到输出:

0.09531017980432487

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